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Read VSEPR as Electron-Pair Repulsion, Not Memorised Shapes

Every VSEPR question is the same underlying task: count electron domains (bonding + lone pairs) around the central atom, place them to minimise repulsion, then read off the molecular shape by ignoring lone pairs in the final description.

NSEC · Chemical Bonding and Molecular Structure · 24 linked questions · 100% coverage
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Chemistry questions first require the material, particles or reaction condition to be identified before a formula or rule is selected.

Observation · What the stem states or showsCondition · The factor that controls the change
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Lone pairs occupy equatorial positions preferentially in trigonal bipyramidal systems

In a 5-electron-domain (trigonal bipyramidal) system like SF₄, ClF₃ or BrF₅, lone pairs always occupy equatorial positions first, since equatorial positions have fewer 90° neighbours than axial ones and lone-pair repulsion is minimised there. This single rule predicts SF4's see-saw shape, ClF3's T-shape, and why BrF₅ has zero 90° F-Br-F angles is a common trap — check the actual geometry (square pyramidal, not trigonal bipyramidal) before assuming the 5-domain rule applies.

Xenon compounds follow the same rules with more lone pairs

XeF₂ (3 lone pairs, linear), XeF₄ (2 lone pairs, square planar) and XeF₆ (1 lone pair, distorted octahedral) form a clean progression — each loses one Xe lone pair as one more F is added, and the number of lone pairs directly determines whether the shape distorts from the parent electron-domain geometry.

Bond angle comparisons need one variable changed at a time

Comparing bond angles down a group (NH₃ > PH₃ > AsH₃ > SbH₃, decreasing due to decreasing central-atom electronegativity and less s-character in bonding orbitals) is a different comparison from comparing across substituents on the same central atom (NH₃ vs NF₃, where electronegative F pulls bonding pairs away from N, shrinking the angle despite F being 'smaller') — identify which variable the question is actually changing before predicting direction.

Matching shapes and identifying incorrect shape claims

For match-the-column and 'which shape is correct' questions, work out hybridisation and lone-pair count for EACH species independently rather than pattern-matching to a memorised list — I³⁻, ICl₂⁻, XeF₂ are all AX₂E₃ systems (linear) despite looking structurally different at first glance.

OlympIQ exam lens

  • ✓Count total electron domains (bonds + lone pairs) first — shape name only describes where the ATOMS are, not the domains.
  • ✓In trigonal bipyramidal (5-domain) systems, lone pairs go equatorial first to minimise 90° repulsions.
  • ✓Xenon fluorides XeF2/XeF4/XeF₆ lose one lone pair each as one more F is added, from 3 down to 1.
  • ✓Bond angle comparisons down a group and bond angle comparisons across substituents on the same atom follow different underlying causes — don't conflate them.
OlympIQ trap

Don't assume every 5-electron-domain molecule has 90° angles between adjacent domains — BrF₅ is square pyramidal (from an octahedral parent with 1 lone pair), not trigonal bipyramidal, so its F-Br-F angles are close to 90° but the axial-lone-pair-vs-basal distinction changes which specific angle comparisons are valid.

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