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Read Entropy Signs Before Predicting Spontaneity

Second-law questions ask you to track a sign — of ΔS, of ΔG, or of a volume/entropy change on a phase transition — more often than they ask you to compute a number.

NSEC · Thermodynamics · 6 linked questions · 100% coverage
Know this first

Second Law: Entropy, Spontaneity & Gibbs Energy is the central idea in this question pattern. Identify the condition in the stem before applying the method below.

Study deeper: NCERT Chemistry · Thermodynamics

Cyclic processes: ΔU returns to zero, entropy doesn't have to

In a full cycle, internal energy returns to its starting value (
ΔU_cycle = 0) since it's a state function

but individual reversible adiabatic segments within that cycle can have zero entropy change while still having nonzero internal-energy change, since Q=0 for an adiabatic step doesn't mean ΔU=0 for that step.

Steam condensing into liquid water: entropy and volume both fall

When steam mixes with liquid water in an isolated system, the system's entropy and volume both decrease as vapour condenses — predicting the sign correctly means recognising condensation as the spontaneous direction here, driven by the surroundings' entropy increase outweighing the system's own entropy decrease.

Reading ΔG° = -RT ln K vs temperature graphs

A plot of RT ln K (or ln K) against T lets you read off the sign and rough magnitude of ΔH° and ΔS° from its slope and intercept, and the temperature range where the reaction is spontaneous (ΔG°<0, i.e. where K>1) directly from where the curve crosses zero.

Intensive properties don't depend on amount

Density, pressure, refractive index and surface tension are intensive (unchanged by how much material you have); volume and heat capacity are extensive (they scale with amount) — sorting a list of properties into these two buckets is really just asking whether doubling the sample doubles the property.

OlympIQ exam lens

  • ✓ΔU_cycle = 0 for any full cycle since internal energy is a state function; entropy change for individual steps within the cycle need not be zero.
  • ✓Spontaneous condensation of steam decreases the system's own entropy — it's the surroundings' larger entropy gain that makes the overall process spontaneous.
  • ✓On a ΔG°=-RT ln K vs T plot, the crossing point where ln K = 0 marks where the reaction becomes spontaneous (K>1).
  • ✓Intensive properties (density, pressure, refractive index, surface tension) don't scale with sample size; extensive ones (volume, heat capacity) do.
OlympIQ trap

Don't assume a spontaneous process always increases the system's own entropy — spontaneity depends on the TOTAL entropy change (system + surroundings), and steam condensing is the classic counterexample where the system's entropy falls.

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