Reactions and Stoichiometry of Alkaline Earth and Alkali Metal Compounds
This cluster is a working set of specific, high-value alkaline-earth and alkali-metal reactions: hydrolysis of a nitride and a carbide, the limestone-to-bicarbonate cycle behind hard water and stalactites, bleaching powder manufacture, and two stoichiometry-based calculation problems.
Stoichiometry of Magnesium Nitride Hydrolysis is the central idea in this question pattern. Identify the condition in the stem before applying the method below.
Nitride and carbide hydrolysis: predictable products from the anion
Ionic nitrides hydrolyse in water to give the metal hydroxide plus ammonia: Mg₃N₂ + 6H₂O → 3Mg(OH)₂ + 2NH₃, so ONE mole of magnesium nitride (which contains 2 nitrogen atoms per formula unit, as N₃⁻) releases TWO moles of ammonia on complete hydrolysis with excess water, not one. Different metal carbides hydrolyse to different hydrocarbons depending on the specific carbon-containing anion present: methanides (C⁴⁻, as in Be₂C or Al₄C₃) give methane; acetylides/dicarbides (C2²-, as in CaC₂) give ethyne (acetylene); and the less common sesquicarbide/allylide ion (C3⁴-, as in Mg₂C₃) gives propyne (methylacetylene) specifically — recognise Mg₂C₃ as the one classic exam example that breaks from the more familiar methane/acetylene pattern.
Bleaching powder and the limestone-lime-bicarbonate cycle
Bleaching powder (calcium oxychloride, roughly CaOCl₂) is made by passing chlorine gas over slaked lime, Ca(OH)₂ (not over quicklime, CaO, directly)
Separately, a classic cycle links three calcium compounds: heating limestone (CaCO₃, compound X) releases CO₂ gas and leaves quicklime (CaO) as a residue; mixing that residue with water gives slaked lime, Ca(OH)₂ (compound Y); passing EXCESS CO₂ through a suspension/solution of Y converts it to the water-soluble calcium bicarbonate, Ca(HCO₃)₂ (compound Z, giving a clear solution, since Ca(HCO₃)₂ is soluble while Ca(OH)₂ and CaCO₃ are not); and boiling that clear solution of Z drives off CO₂ and reforms solid CaCO₃ (compound X), completing the cycle. This exact cycle (limestone to lime to bicarbonate solution to limestone again on boiling) is the chemistry behind temporary hard water and behind stalactite/stalagmite formation in caves.
Titration stoichiometry for a two-metal mixture
When a mixture of two Group 1 metals reacts completely with water, each mole of metal (regardless of which one) releases exactly one mole of hydroxide ion, since each is a +1 cation. Neutralising the resulting mixed hydroxide solution with a known volume and molarity of a diprotic acid like H₂SO₄ (which neutralises 2 moles of OH⁻ per mole of acid) lets you calculate the TOTAL moles of metal present from the acid used; combining that total-moles equation with the given total MASS of the mixture (via each metal atomic mass) gives two simultaneous equations in two unknowns, solvable for the mass of each individual metal — the calculation works the same way regardless of which two alkali metals are mixed, since basicity (charge) is identical across the group.
Milk of magnesia is a suspension, not a solution
Magnesium hydroxide, Mg(OH)₂, is only very sparingly soluble in water. Milk of magnesia (the familiar antacid) is prepared as a SUSPENSION of finely divided, undissolved Mg(OH)₂ particles dispersed in water, not a true solution (which would require the compound to actually dissolve at the molecular/ionic level) and not a colloid either (a suspension has larger, visible/settling particles, distinct from the much smaller, stably dispersed particles of a true colloid) — the deliberately low aqueous solubility of Mg(OH)₂ is exactly what makes it useful as a slow-acting, sustained-release antacid rather than a fast-dissolving one.
OlympIQ exam lens
- ✓Mg₃N₂ + 6H₂O gives 3Mg(OH)₂ + 2NH₃ — one mole of nitride releases TWO moles of ammonia, not one
- ✓Mg₂C₃ (the sesquicarbide/allylide, C3⁴-) hydrolyses to propyne, distinct from methanides (to methane) and acetylides like CaC₂ (to ethyne)
- ✓Bleaching powder is made from Cl₂ + Ca(OH)₂ (slaked lime), not Cl₂ + CaO directly
- ✓The limestone cycle: CaCO₃ to CaO (heat) to Ca(OH)₂ (add water) to Ca(HCO₃)₂ (excess CO₂, gives a clear soluble solution) to CaCO₃ again (boiling drives off CO₂)
- ✓For a two-metal titration problem, each mole of Group 1 metal gives one mole of OH⁻; combine total-moles-from-acid with total-mass to solve for each metal individual mass
- ✓Milk of magnesia is a SUSPENSION of Mg(OH)₂, not a true solution or a colloid — its low solubility is what makes it a sustained-release antacid
Do not assume one mole of a binary nitride gives one mole of ammonia on hydrolysis. Count the nitrogen atoms in the formula first — Mg₃N₂ contains two nitrogens per formula unit, so complete hydrolysis of one mole of Mg₃N₂ gives two moles of NH₃, not one.
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