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Calculate CFSE and Magnetic Moment from d-Electron Count

Both CFSE and magnetic moment reduce to one skill: correctly filling t2g/eg (or e/t2 for tetrahedral) with the right number of d-electrons, given the metal's oxidation state and the ligand's field strength.

NSEJS · Coordination Compounds and Organometallics · 9 linked questions · 100% coverage
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Electricity questions depend on identifying charge, a conducting path and the condition that controls current or magnetic effect.

Current · Flow of electric chargeCircuit · A complete conducting loopResistance · Opposition to current
Study deeper: NCERT Science · Coordination Compounds and Organometallics

Counting unpaired electrons drives paramagnetism

[Cu(H2O)4]2+ and [Cu(NH3)4]2+ are both Cu2+ (d9) regardless of ligand, so both have exactly 1 unpaired electron and the same spin-only magnetic moment: μ = √(n(n+2)) = √3 = 1.73 BM for both. Choose B. A high-spin d6 ion with a weak-field ligand keeps more unpaired electrons than the same d6 ion with a strong-field ligand — ligand strength, not just d-count, decides pairing.

Spin-only formula across common configurations

μ = √(n(n+2)) BM where n = unpaired electrons: n=1 → 1.73 BM, n=3 → 3.87 BM, n=4 → 4.90 BM, n=5 → 5.92 BM

A high-spin d5 ion like [FeF6]3- or [MnCl6]3- has 5 unpaired electrons (maximum possible for any configuration) and the highest simple spin-only moment among first-row transition ions.

d8 across three geometries gives three different answers

A d8 ion's magnetic moment depends entirely on geometry: octahedral d8 keeps 2 unpaired electrons (2.8 BM), tetrahedral d8 also keeps 2 unpaired (2.8 BM, since Δt is too small to force pairing), but square planar d8 pairs completely (0 BM, diamagnetic) — because the dx2-y2 orbital is pushed high enough that all electrons pair into the four lower orbitals.

CFSE follows the electron-filling pattern, not just d-count

High-spin d4 has
CFSE = −0.6Δo (3 electrons in t2g at −0.4Δo each, 1 in eg at +0.6Δo: 3(−0.4)+1(0.6) = −0.6)

CFSE magnitude doesn't rise smoothly across a d-electron series for same-charge ions, because half-filled and fully-filled t2g/eg configurations reset the stabilisation calculation each time.

OlympIQ exam lens

  • ✓Same metal ion (same d-count) can still have different unpaired-electron counts if ligand field strength differs.
  • ✓Spin-only formula: μ = √(n(n+2)) BM — memorise 1.73, 2.83, 3.87, 4.90, 5.92 for n = 1 through 5.
  • ✓d8 is diamagnetic (0 BM) ONLY in square planar geometry; it stays paramagnetic (2.8 BM) in both octahedral and tetrahedral.
  • ✓CFSE must be computed by filling t2g (−0.4Δo each) and eg (+0.6Δo each) according to the actual high-spin/low-spin pattern, not just counted from d-electron total.
OlympIQ trap

Don't assume identical d-electron count means identical magnetic moment — ligand field strength and geometry both change how those electrons actually fill the orbitals. Square planar d8 is the single most-tested exception (diamagnetic, unlike octahedral/tetrahedral d8).

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