OlympIQ
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Combine Springs Like Capacitors, Then Use T = 2π√(m/k)

A mass on a spring oscillates with ω = sqrt(k/m). When several springs are used, first reduce them to one effective force constant, then use the same formula.

NSEJS · Oscillations · 3 linked questions · 100% coverage
Know this first

Spring-Mass Systems and Spring Combinations is the central idea in this question pattern. Identify the condition in the stem before applying the method below.

Study deeper: NCERT Science · Oscillations

Series and parallel

Springs in parallel (sharing the same displacement) add their constants,
k=k1+k2k = k1 + k2
Springs in series (sharing the same force) combine as 1/
k=1/k1+1/k2,sok=k1k2/(k1+k2)k = 1/k1 + 1/k2, so k = k1 k2 / (k1 + k2)

A combination of effective constant K/2 and another of effective constant 2K/3 give frequencies in the ratio sqrt((K/2) / (2K/3)) = sqrt(3)/2, since f is proportional to sqrt(k).

Comparing two oscillators

For equal masses on springs of constants k1 and k2 with equal maximum speeds, v_max = A sqrt(k/m) gives A1 sqrt(k1) = A2 sqrt(k2), so the ratio of the amplitudes is A1 / A2 = sqrt(k2 / k1): the stiffer spring has the smaller amplitude.

OlympIQ exam lens

  • ✓Parallel springs: k = k1 + k2; series: k = k1 k2 / (k1 + k2)
  • ✓f = (1/2π) sqrt(k / m); T = 2π sqrt(m / k)
  • ✓Equal maximum speeds and equal masses: amplitude is proportional to 1/sqrt(k)
OlympIQ trap

Do not add spring constants for springs in series. Series springs share the same force but stretch by different amounts, so the effective constant is smaller than either spring, exactly as the effective capacitance of capacitors in series is smaller than either capacitor.

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