NaOH as a Reagent: Disproportionation, Industrial Byproducts and Applications
Hot concentrated sodium hydroxide is more than just a base — it drives disproportionation reactions in several nonmetals, and NaOH itself is both a product and a reagent in a handful of important industrial and everyday processes.
Byproduct of Sodium Hydroxide Manufacture is the central idea in this question pattern. Identify the condition in the stem before applying the method below.
Hot NaOH disproportionates boron, phosphorus and sulfur
Several nonmetals undergo disproportionation (simultaneous oxidation and reduction of the same element) when treated with hot concentrated NaOH. Boron reacts with hot NaOH to give sodium borate plus hydrogen gas (2B + 2NaOH + 2H2O → 2NaBO2 + 3H2, sometimes written toward Na3BO3-type products depending on conditions) — boron is oxidized while some hydrogen is released. White phosphorus (P4) disproportionates in hot NaOH solution to give sodium hypophosphite (NaH2PO2, phosphorus oxidized to +1) and phosphine gas (PH3, phosphorus reduced to -3) — a classic reaction. Sulfur disproportionates in hot concentrated NaOH to give sodium thiosulfate (Na2S2O3) and sodium sulfide (Na2S) together with water — again splitting the same starting element into a more-oxidized and a more-reduced product simultaneously. All three of these are genuine, textbook-correct disproportionation reactions of NaOH with a nonmetal.
Tracing a boron reagent sequence: fluoride to hydride to acid
A boron trifluoride-type compound (BF3, as the compound Z) reduced by excess lithium aluminium hydride gives diborane, B2H6 (compound X), releasing LiF and AlF3 as by-products of the reduction. Diborane then hydrolyses readily in water to give boric acid, H3BO3 (compound Y), releasing hydrogen gas in the process (B2H6 + 6H2O → 2H3BO3 + 6H2). Separately, diborane burns readily in oxygen (it is highly reactive and pyrophoric-adjacent) to give boron oxide, B2O3, and water, releasing a large amount of energy — this combustion reactivity is part of why diborane has been explored as a high-energy fuel additive. Reading a sequence like this means tracking each compound through one transformation at a time: reduction of a fluoride gives the hydride, hydrolysis of the hydride gives the oxyacid, and combustion of the hydride gives the oxide.
NaOH manufacture, and two classic sodium-compound applications
Industrially, sodium hydroxide is manufactured by the chlor-alkali process: electrolysis of concentrated aqueous NaCl (brine), which produces NaOH at the cathode compartment while chlorine gas, Cl2, is released as the co-product at the anode (hydrogen gas is also released at the cathode alongside NaOH, but among the given classic options, Cl2 is the standard byproduct answer). Two other sodium compounds show up in specific applications worth remembering by name: sodium thiosulfate, Na2S2O3 (commonly called hypo), is the standard photographic fixer, dissolving away unexposed silver halide from photographic film after development; and, in a linked industrial reaction sequence starting from Na2CO3 treated with water and CO2 to give NaHCO3, then combined with ZnCl2 and heated, the resulting zinc compound eventually decomposes to ZnO, which — being amphoteric — dissolves in excess NaOH to form sodium zincate, Na2ZnO2, the final product in that sequence.
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- ✓Hot NaOH disproportionates B (to borate + H2), P4 (to NaH2PO2 + PH3) and S (to Na2S2O3 + Na2S) — all genuine disproportionation reactions
- ✓BF3 reduced by LiAlH4 gives B2H6 (diborane); B2H6 hydrolyses to H3BO3 (boric acid); B2H6 burns in O2 to give B2O3
- ✓The chlor-alkali process (electrolysis of brine) gives NaOH at the cathode with Cl2 released as the byproduct
- ✓Sodium thiosulfate (Na2S2O3, hypo) is the standard photographic fixer
- ✓An amphoteric zinc oxide intermediate dissolves in excess NaOH to give sodium zincate, Na2ZnO2
Do not treat the reaction of P4, B or S with hot NaOH as a simple acid-base neutralisation. Each of these is a genuine disproportionation: the same element ends up split between a more-oxidized product and a more-reduced product in the same reaction, not a single straightforward salt-forming step.
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