Run a Carnot Engine Backwards: COP = Tc / (Th - Tc)
A refrigerator is a heat engine run in reverse: work is put in, heat is taken from the cold space and a larger amount is rejected to the warm surroundings. Its figure of merit is the coefficient of performance (COP), not the efficiency.
Refrigerators and Coefficient of Performance is the central idea in this question pattern. Identify the condition in the stem before applying the method below.
COP and the heat balance
Finding temperatures from the COP
Invert the formula when the COP is given: with COP = 5 and a freezer at -20 °C (253 K), Th - 253 = 253/5 = 50.6 K, so the surroundings are at about 303.6 K, roughly 30.6 °C. For a refrigerator working between 4 °C (277 K) and 30 °C (303 K), COP = 277/26, about 10.7, so removing 300 calories per second requires about 28 calories per second of work.
A Carnot engine used as a refrigerator
An engine of efficiency 1/20 used as a refrigerator therefore has COP = (19/20)/(1/20) = 19, so 20 J of work removes 19 x 20 = 380 J from the cold reservoir.
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- ✓COP = Qc / W; for a reversible refrigerator COP = Tc / (Th - Tc), kelvin only
- ✓Heat rejected to the surroundings = Qc + W
- ✓Power = heat removed per second divided by COP
- ✓Invert COP = Tc/(Th - Tc) to find Th from a given COP
- ✓An engine with efficiency η, run backwards, has COP = (1 - η)/η
Do not call COP an efficiency or expect it to be below 1. A refrigerator's COP is usually well above 1 because it moves more heat than the work it consumes; the smaller the temperature gap, the larger the COP.
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