OlympIQ
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Find Wave Speed from the Medium, Then Use f and λ

A wave's speed is set by the medium, its frequency by the source, and its wavelength follows from v = f λ. Most speed questions are about which of these is unchanged when something else changes.

NSEJS · Wave Motion and Doppler's Effect · 9 linked questions · 100% coverage
Know this first

Motion and force questions become simpler when direction, starting condition, time and the acting forces are marked first.

Distance · Length of the path travelledDisplacement · Straight-line change in positionResultant force · Net force including direction
Study deeper: NCERT Science · Wave Motion and Doppler's Effect

Speed on strings and ropes

On a string the speed
v = sqrt(T/μ)

For y = 0.02 sin[2π(t/0.04 - x/0.50)], the period is 0.04 s and the wavelength 0.50 m, so v = 12.5 m/s and, with μ = 0.04 kg/m, the tension is T = μ v² = 6.25 N. In a uniform rope hanging from a ceiling, the tension at a distance x from the free lower end is μ g x, so v = sqrt(g x): at the top of a 2.5 m rope v = sqrt(10 x 2.5) = 5 m/s and at 0.5 m from the lower end v = sqrt(10 x 0.5) = 2.24 m/s, so the wave slows toward the bottom.

Sound in different media; P and S waves

Sound travels faster in moist air than in dry air, because moist air is less dense. When sound passes from water (1450 m/s) into air (330 m/s) the frequency is unchanged, since it is set by the source, while the speed falls, so the wavelength falls too. For earthquake waves, the difference in arrival time is Δt = d (1/v_S - 1/v_P), so d = Δt v_S v_P / (v_P - v_S): with Δt = 4 min = 240 s, v_S = 4.5 km/s and v_P = 8.0 km/s, d is about 2500 km.

Echoes and intensity

For an echo, the sound travels to the reflector and back, so
distance = v t / 2: 340 m/s x 1 s / 2 = 170 m

The intensity of a wave is proportional to the square of the amplitude and the square of the frequency, I proportional to A² f². If the amplitude doubles the intensity is multiplied by 4, and if the frequency becomes one fourth the intensity is multiplied by 1/16, so the net intensity is 1/4 of the original.

OlympIQ exam lens

  • ✓String wave speed v = sqrt(T/μ); for a hanging rope v = sqrt(g x), x from the free end
  • ✓Frequency is fixed by the source; speed and wavelength change from one medium to another, with v = f λ
  • ✓Sound is faster in moist air than in dry air
  • ✓P-S arrival gap: d = Δt v_S v_P / (v_P - v_S)
  • ✓Echo distance = v t / 2; intensity is proportional to A² f²
OlympIQ trap

Do not say the frequency changes when a wave enters another medium. The frequency stays the same and the speed changes, so the wavelength changes in proportion to the speed.

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