OlympIQ
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Use F = qv × B and the Right-Hand Rules, and Reverse the Result for Negative Charge

Magnetism questions ask about the direction of a force on a moving charge, the direction of curvature of a track, or the field produced by a current. The right-hand rule gives all three, and the only extra step is reversing the result for a negative charge.

NSEJS · Moving Charges and Magnetism · 5 linked questions · 100% coverage
Know this first

Electricity questions depend on identifying charge, a conducting path and the condition that controls current or magnetic effect.

Current · Flow of electric chargeCircuit · A complete conducting loopResistance · Opposition to current
Study deeper: NCERT Science · Moving Charges and Magnetism

Force on a moving charge

F=qv×BF = q v \times B

For a positive charge, the direction of v × B is the direction of the force; for a negative charge such as an electron it is the opposite. An electron projected east and deflected north needs v × B to point south: with east = +x and north = +y, v × B must be along -y, and x × B = -y when B is +z, so the field points upward. A magnetic force is always perpendicular to the velocity, so it changes the direction of motion but not the speed;

the radius of the circular path
r=mv/(qB)r = m v / (q B)

A neutral particle such as a neutron feels no magnetic force.

Reading a curved track

In a cloud chamber the sense of curvature tells the sign of the charge for a given direction of travel. Reversing both the sign of the charge and the direction of travel gives the same curvature, so a track that suits a proton or an α particle going from p to q is also compatible with an electron going from q to p, but not with a neutron. A larger charge-to-mass ratio, or a smaller momentum, gives a tighter curve.

Fields of currents

A long straight wire gives
B = μ0 I / (2π r), with the direction from the right-hand grip rule

For a hairpin conductor with currents in opposite directions on two parallel arms, the fields of the two arms add in the region between them and partly cancel outside.

Inside a long solenoid the field is uniform,
B = μ0 n I along the axis;

it falls to about half this value at the ends and is negligible outside, so a point at the centre of a long solenoid has the largest field.

OlympIQ exam lens

  • ✓F = q v × B; reverse the direction for a negative charge
  • ✓The magnetic force never changes speed; the circular radius is m v / (q B)
  • ✓Reversing both the charge sign and the direction of travel gives the same curvature; neutral particles go straight
  • ✓Long wire: B = μ0 I / 2π r; two opposite currents add between the wires
  • ✓Long solenoid: B = μ0 n I, uniform inside, about half at the ends, nearly zero outside
OlympIQ trap

Do not forget the sign of an electron. The right-hand rule gives the force on a positive charge; for an electron the force is opposite, so a field direction worked out for a positive charge is reversed.

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