OlympIQ
Read before you solve · 3 min

Read Vertical Strings: Let Tension Vary with Height

Pulse speed on a string is square-root(T/λ), but a hanging string has tension that changes with distance from the support.

NSEP · Waves and Sound · 1 linked question · 100% coverage
Know this first

Transverse Pulses on a Vertical String is the central idea in this question pattern. Identify the condition in the stem before applying the method below.

Study deeper: NCERT Physics · Waves and Sound

Start with the condition

At depth x from the top, tension supports the string below that point.

Integrate dt = dx divided by square-root(T(x)/λ) and compare with the falling ball's time

Build the governing relation

Use the mass of the hanging portion, not the full string, when writing local tension.

Finish with a physical check

Check the limiting case before selecting an option: remove the special feature in the diagram or make the relevant parameter very large or very small. The result should reduce to a familiar relation.

OlympIQ exam lens

  • ✓State the physical condition before choosing a formula.
  • ✓Keep direction, sign and constraint information explicit.
  • ✓Test one limiting case before committing to an option.
OlympIQ trap

Applying one constant wave speed to the entire vertical string ignores its varying tension.

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