OlympIQ
Read before you solve · 3 min

Read EM Waves: Make E Perpendicular to the Wave Vector

This short read prepares one exact NSEP pattern: plane em wave transversality and energy. Identify the physical condition before calculating.

NSEP · Electromagnetic Induction · 1 linked question · 100% coverage
Know this first

Plane EM Wave Transversality and Energy is the central idea in this question pattern. Identify the condition in the stem before applying the method below.

Study deeper: NCERT Physics · Electromagnetic Induction

Start with the physical model

Read the configuration once, state the conserved quantity or governing law, and mark any changing geometry, sign convention or limiting condition.

Build the relation

The phase is 107(x+2y+3z-βt), so |k|=107√(12+22+32)=107√14.

For an EM wave,
ω = c|k| and ω=107β, hence β=3×108√14: A is correct

The field amplitude is proportional to 3j + b k.

Transversality E· k = 0 gives 3(2)+b(3)=0, so b=-2, not +2;

B is false. Then E0 2=13×10-6, and average total energy density is u=ε0E0 2/2 = 6.5×10-6ε0: C.

B0=E0/c≈1.20×10−11T:DB0 = E0/c≈1.20\times 10-11 T: D

Correct A,C,D.

Check before selecting

Check units, sign and one limiting case. A valid result must still fit the original geometry and stated constraint.

OlympIQ exam lens

  • ✓Name the governing law before using a formula.
  • ✓Keep the stated geometry and direction information explicit.
  • ✓Use one unit or limiting-case check.
OlympIQ trap

The coefficients in the phase set the wave-vector direction; do not confuse them with field components.

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